1.

The flux linked with a coil of self-inductance 2when there is a current of 5.8 A flowing through it, is(1) 11.6 Wb(2) 2.9 Wb3) 8.7 Wb4) dependent on the orientation of the coil

Answer»

L = ∅/I => ∅ = LI = 2*5.8 = 11.6wb option A should be correct.. without considering the orientation of the coil , assuming all magnetic lines flow through the area.of coil



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