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The focal length of a convex lens is 20 cm. If an object of height 2 cm is placed at 30 cm from the lens, find (i) the position and nature of the image(ii)the height of the image (iii) the magnification produced by the lens. |
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Answer» Solution :`1/f 1/v - 1/u` ` therefore1/u = 1/f + 1/u = 1/(20 cm) + 1/(- 30 cm) = 1/( 20 cm) - 1/ (30 cm)` ` = ( 3-2)/( 60 cm) = 1/( 60 cm)` v= 60 cm , v is positive. The image will be formed at 60 cm from the lens and on the other side of the lenswith RESPECT to the OBJECT. It is a real image. (ii) ` h_(2)/h_(1) = u/v` ` h_(2)/(2 cm) = (60 cm)/(-30 cm) = -2 ` `h_(20 = -2 XX 2 cm = - 4 cm` `h_(2) ` is negative. This shows that the image is inverted . The height of the image = - 4 cm (III) ` M = h_(2)/h_(1) = ( - 4 cm)/(2 cm) = -2 ` M is negative, indicating that teh image is inverted. The magnification produced by the lens = -2 |
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