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The following data were obtained during the first order thermal decomposition of `SO_(2)Cl_(2)` at a constant volume `SO_(2)Cl_(2)(g)to SO_(2)(g)+Cl_(2)(g)` Calculate the rate of the reaction when total pressure is 0.65 atmA. `0.35 atmS^(-1)`B. `2.235 xx10^(-3)atmS^(-1)`C. `7.8xx10^(-4) atm s^(-1)`D. `1.55 xx10^(-4) atm S^(-1)` |
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Answer» Correct Answer - C ` SO_(2) Cl_(2 ) to SO_(2) +Cl_(2)` initial pressure ` P_(0) ,0,0` Pressure pressure `P_(0)-p " " P" " p` Let initial pressure `p_(0) prop R_(0)` pressure at time t, `P_(t) =p_(0)-p+p+p=P_(0) +p` Pressure of reactants at time t ` p_(0)-P=2P_(0)-p_(1)prop R` `k=(2.303)/(t) log ""(p_(0))/(2p_(0)-p_(t))` ` =(2.303)/(100) log""(0.5)/(2xx0.5-0.6)=(2.303)/(100) log 1.25 ` `=2.318 xx10^(-3)S^(-1)` pressure of `SO_(2)Cl_(2)` at time `t (P_(SO_(2)Cl_(2))) ` `=2p_(0)-P_(t) =2xx0.50-0.65 atm + 0.35 atm ` rate at that time `=k xxp_(SO_(2)Cl_(2))` `=(2.318xx10^(-3))xx(0.35)=7.8 xx10^(-4) atmS^(-1)` |
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