InterviewSolution
Saved Bookmarks
| 1. |
The following reaction was carried out in water : `Cl_(2) + 2I^(ɵ) rarr I_(2) + 2Cl^(ɵ)` The initial concentration of `I^(ɵ)` was `0.25 mol L^(-1)` and the concentration after `10 min` was `0.23 mol L^(-1)`. Calculate the rate of disappearance of `I^(ɵ)` and rate of appearance of `I_(2)`. |
|
Answer» `Delta[I^(-)]=[I^(-)]_("final")-[I^(-)]_("initial")` `=0.23-0.25=-0.02"mol" L^(-1)` `Deltat=10-0=10` min `-(Delta[I^(-)])/(Deltat)=-((0.02))/(10)=0.02 "mol" L^(-1) "min"^(-1)` Rate of apperance of `I_(2)-(1)/(2)(Delta[I^(-)])/(Deltat)=(0.002)/(2)` `= 0.001 "mol" L^(-1) min ^(-1)` |
|