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!the following velocity-time graph of a body.ctdistance and displacement travelled by the bod5 second in meters will be-4030-20-1003075 11545, 75(8) 105, 75(D) 95, 55) |
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Answer» Displacement = area under the curve = 1/2*(20*2) + (20*2) + (1*20) + 1/2*(20*1) - 1/2*(30*1)= 20 + 40 + 20 +10 - 15= 90-15= 75 and distance = 90+15 = 105 option B |
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