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The force of surface tension on a ring situated on the surface of water is ` 14 pi xx 10^(-4)` N . Then the diameter of the ring isA. 5 mmB. 1 cmC. 2 cmD. 4 cm |
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Answer» Correct Answer - B `T =F/(4pir)= F/(2pid)` ` :. D = (14 pi xx 10^(-4))/(2xxpixx70xx10^(-3)) = 0.01 m = 1 cm` |
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