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The force on a rocket moving with a veloctiy 300 m/s is 210N. The rate of consumption of fuel of rocket isA. `0.07 kg s^(-1)`B. `1.4kg s^(-1)`C. `0.7kg s^(-1)`D. `10.7kg s^(-1)` |
Answer» Correct Answer - C Force `=(d)/(dt)` (momentum) `(d)/(dt)("mv")=v((dm)/(dt)) Rightarrow 210=300((dm)/(dt))` rate of combustion, `(dm)/(dt)=(210)/(300)=0.7 kg s^(-1)` |
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