1.

The frequencies of two sound sources are 256 Hz and 260 Hz, At `t=0` the intesinty of sound is maximum. Then the phase difference at the time `t=1//16` sec will beA. zeroB. `pi`C. `pi//2`D. `(pi)/(4)`

Answer» Correct Answer - C
Time arrival between two consecutive beats
`T=(1)/(n_1-n_2)=(1)/(260-250)=(1)/(4)`sec so, `(1)/(16)=(T)/(4)`sec
By using time difference `=(T)/(2pi)xx`phase difference
`implies(T)/(4)=(T)/(2pi)xxphiimpliesphi=(pi)/(2)`


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