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The front axle of a car has pivot centers 1.3 m apart. The angle of inside lock is 40℃ and the angle of the outside lock is 35℃. What is the wheelbase of the car?(a) 5.5 m(b) 3.5 m(c) 4.5 m(d) 6.5The question was posed to me in class test.The query is from Steering System in division Steering & Front Axle of Automobile Engineering

Answer»

Correct answer is (a) 5.5 m

Best explanation: For correct steering, cot α – cot θ = c / B where c = PIVOT center, b = WHEELBASE, α = angle of outside LOCK, and θ = angle of inside lock. Cot α – Cot θ = c / b ⇒ Cot 35 – Cot 40 = 1.3 / b⇒ b = 5.49 m.



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