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The fundamental frequency of an open pipe of length 34cm and how many harmonics may be heard by a person having normal hearing ?A. 100Hz, 10B. 300 Hz, 30C. 200 Hz, 20D. 500 Hz, 40

Answer» Correct Answer - D
`n_0 = (v)/(2l) = (340)/(2xx34xx10^(-2)) = 500Hz`
Number of harmonics `=20000/500=40`


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