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The gaseous decomposition of ozome `2O_(3)rarr3O_(2)` obeys the rate law `r=-(d[O_(3)])/(dt)=(k[O_(3)]^(2))/([O_(2)])` Show that the following mechanims is consistent with the above rate law : `O_(3)overset(K_(eq))hArrO_(2)+O" " ("fast")` `O+O_(3)overset(k_(1))rarr2O_(2)" " ("slow")` |
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Answer» From the slow rate determining step `=-(d[O_(3)])/(dt)=k_(1)[O][O_(3)]` From the fast reaction., `K_(eq)=([O_(2)][O])/([O_(3)])` or `[O]=(K_(eq)[O_(3)])/([O_(2)])` Substituting the value of [O] in the above expression `r=-(d[O_(3)])/(dt)=(k_(1)K_(eq)[O_(3)]^(2))/([O_(2)])=(k[O_(3)]^(2))/([O_(2)])` |
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