1.

The general solution of the trigonometric equation `tan^2theta=1` isA. `theta=n pi pm(pi)/(3), n in z`B. `theta = npi pm(pi)/(6), n in z`C. `theta=n pi pm (pi)/(4), n in z`D. `theta = n pi, n in z`

Answer» Correct Answer - C
`tan^(2)theta = tan alpha`
`theta= n pi pm alpha`
`tan^(2)theta=1`
`tan^(2) theta=tan^(2).(pi)/(4)`
`therefore" "theta=n pi pm(pi)/(4)`


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