InterviewSolution
Saved Bookmarks
| 1. |
The general term of a sequence is given by an = - 4n2 + 15.Is the sequence an A.P..? If so, find its 15th term and the common difference. |
|
Answer» Put n = 1 a1 = - 4(1)2 + 15 = 11 Put n = 2 a2 = - 4(2)2 + 15 = -1 Put n = 3 a3 = - 4(3)2 + 15 = -21 Common difference, d1= a2 – a1 = -1 – 11 = -12 Common difference, d2= a3 – a2 = - 21 + 1 = 20 Since, d1 ≠ d2 Therefore, it’s not an A.P |
|