The generated e.m.f from 16-pole armature having 57 turns driven at 78 rev/sec having flux per pole as 5 mWb, with lap winding is ___________(a) 44.16 V(b) 44.15 V(c) 44.46 V(d) 44.49 VThe question was asked in quiz.The doubt is from DC Motors topic in portion Characteristics of DC & AC Motors of Electric Drives

The generated e.m.f from 16-pole armature having 57 turns driven at 78

1.	The generated e.m.f from 16-pole armature having 57 turns driven at 78 rev/sec having flux per pole as 5 mWb, with lap winding is ___________(a) 44.16 V(b) 44.15 V(c) 44.46 V(d) 44.49 VThe question was asked in quiz.The doubt is from DC Motors topic in portion Characteristics of DC & AC Motors of Electric Drives
Answer» The correct option is (c) 44.46 V To explain I would say: The generated e.m.f can be calculated using the formula Eb = Φ×Z×N×P÷60×A, Φ represent flux per pole, Z REPRESENTS the TOTAL number of conductors, P represents the number of poles, A represents the number of parallel paths, N represents speed in rpm. One turn is EQUAL to two conductors. In lap winding, the number of parallel paths is equal to a number of poles. Eb = .005×16×57×2×4680÷60×16=44.46 V.

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