The generated e.m.f from 20-pole armature having 800 conductors driven at 30 rev/sec having flux per pole as 60 mWb, with 16 parallel paths is ___________(a) 1900 V(b) 1840 V(c) 1700 V(d) 1800 VThis question was posed to me in an interview.The origin of the question is DC Motors Characteristics in chapter Characteristics of DC & AC Motors of Electric Drives

The generated e.m.f from 20-pole armature having 800 conductors driven

1.	The generated e.m.f from 20-pole armature having 800 conductors driven at 30 rev/sec having flux per pole as 60 mWb, with 16 parallel paths is ___________(a) 1900 V(b) 1840 V(c) 1700 V(d) 1800 VThis question was posed to me in an interview.The origin of the question is DC Motors Characteristics in chapter Characteristics of DC & AC Motors of Electric Drives
Answer» The correct choice is (d) 1800 V To elaborate: The generated e.m.f can be calculated using the formula Eb = Φ×Z×N×P÷60×A, Φ represent flux per pole, Z represents the TOTAL number of conductors, P represents the number of POLES, A represents the number of parallel PATHS, N represents speed in rpm. Eb = .06×20×1800×800÷60×16 = 1800 V.

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