The generated e.m.f from 22-pole armature having 75 turns driven at 78 rpm having flux per pole as 400 mWb, with lap winding is ___________(a) 76 V(b) 77 V(c) 78 V(d) 79 VI had been asked this question in homework.The query is from Methods to Reduce the Energy Loss During Starting topic in chapter Starting of Electric Drives

The generated e.m.f from 22-pole armature having 75 turns driven at 78

1.	The generated e.m.f from 22-pole armature having 75 turns driven at 78 rpm having flux per pole as 400 mWb, with lap winding is ___________(a) 76 V(b) 77 V(c) 78 V(d) 79 VI had been asked this question in homework.The query is from Methods to Reduce the Energy Loss During Starting topic in chapter Starting of Electric Drives
Answer» Correct option is (c) 78 V Best explanation: The generated e.m.f can be calculated using the formula Eb = Φ×Z×N×P÷60×A, Φ REPRESENT flux PER pole, Z represents the total number of conductors, P represents the number of poles, A represents the number of parallel paths, N represents SPEED in rpm. One turn is equal to two conductors. In lap winding, the number of parallel paths is equal to a number of poles. Eb = .4×22×75×2×78÷60×22 = 78 V.

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