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The given diagram represents a screw gauge. The circular scale is divided into `50` divisions and the linear scale is divided into millimeters. If the screw advances by `1 mm` when the circular scale makes `2` complete revolutions, find the least count of the instrument and the reading of the instrument in the figure. . |
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Answer» Correct Answer - A::B::C Pitch of the screw = `(1 mm)/ 2` = `0.5 mm` Least count = `(0.5)/(50)` = `0.01 mm` Reading = Linear scale reading + (coinciding circular scale `xx` least count) = `3.0 mm +(32 xx 0.01) = 3.0 + 0.32` = `3.32 mm`. |
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