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The given equi-convex lens is broken into four parts and rearranged as shwon. If the initial focal length is f, then after rearrangement the equivalent focal length is A. `f`B. `f//2`C. `f//4`D. `4f` |
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Answer» Correct Answer - B Focal length of any one part will be `2f.` `:. 1/F=1/(2f)+1/(2f)+1/(2f)+1/(2f) or F=f/2` |
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