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The gradient of climb is given by _____________(a) \(\Big[\frac{\eta P}{V}-W\Big]\frac{1}{D}\)=sinγ2(b) \(\Big[\frac{\eta P}{V}+D\Big]\frac{1}{W}\)=sinγ2(c) \(\Big[\frac{\eta P}{V}-D\Big]\frac{1}{W}\)=sinγ2(d) \(\Big[\frac{\eta P}{V}+W\Big]\frac{1}{D}\)=sinγ2The question was posed to me in exam.My enquiry is from Climb and Descent Performance with Power-Producing Engines in section Climb and Descent Performance of Aircraft Performance

Answer»

Right answer is (c) \(\Big[\frac{\eta P}{V}-D\Big]\frac{1}{W}\)=sinγ2

Best explanation: The gradient of climb is GIVEN by \(\Big[\frac{\eta P}{V}-D\Big]\frac{1}{W}\)=sinγ2 where η is propeller EFFICIENCY, P is power, V is velocity, D is drag and γ is the angle at which the force is acting on the aircraft. The value of gradient of climb is more when the propulsive force is maximum.



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