1.

The Graph given shows the positions of a body art different times.Calculate the Speed of the body as it moves from:(i) A to B(ii) B to C, and(iii) C to D​

Answer»

\Large{\bf{\green{\mathfrak{\dag{\underline{\underline{Given:-}}}}}}}

  • Graph shows the POSITIONS of a body at different times.

\Large{\bf{\orange{\mathfrak{\dag{\underline{\underline{To \: Find:-}}}}}}}

  • Speed of the body,

  • (i) A to B

  • (ii) B to C

\Large{\bf{\red{\mathfrak{\dag{\underline{\underline{Solution:-}}}}}}}

We know that,

\boxed{\pink{\sf Speed \: = \: \dfrac{Distance}{Time}}}

First let's take,

  • A to B

  • Distance covered from A to B =

  • Final distance covered - intial start =

  • 3 - 0 = 3cm

  • Time taken =

  • Final time taken taken - starting time =

  • 5 - 0 = 5s

  • Speed =

  • \sf Speed \: = \: \dfrac{3}{5}

THEREFORE,

  • \boxed{\purple{\textsf{Speed from A to B = 0.6 cm/s.}}}

Second let's take,

  • B to C

  • Distance covered from B to C =

  • Final distance covered - initial start =

  • 3 - 3 = 0cm

This implies that,

  • Body is at rest.

  • Time taken =

  • Final time taken - starting time =

  • 7 - 5 = 2s

  • Speed =

  • Since, distance i.e numerator is 0.

Therefore,

  • \boxed{\purple{\textsf{Speed from B to C = 0 m/s i.e at rest.}}}

Third let's take,

  • C to D

  • Distance covered from A to B =
  • Final distance covered - intial start =

  • 7 - 3 = 4cm

  • Time taken =

  • Final time taken taken - starting time =

  • 9 - 7 = 2s

  • Speed =

  • \sf Speed \: = \: \dfrac{4}{2}

Therefore,

  • \boxed{\purple{\textsf{Speed from C to D = 2 cm/s.}}}

Finally,

  • Speed from A to B = 0.6 cm/s.

  • Speed from B to C = 0 cm/s.

  • Speed from C to D = 2 cm/s.


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