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The gravitational field due to a mass distribution is given by `E=K/x^3` in X-direction. Taking the gravitational potential to be zero at infinity, find its value at a distance x.A. `K//x`B. `K//2x`C. `K//x^(2)`D. `K//2x^(2)` |
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Answer» Correct Answer - D Since, `I = - dV//dr` or `dV = - I dr` So, `V = underset(0) overset(x)int - I dr = underset(0) overset(x)int - K r^(-3) dr` `= - K((r^(-3+ 1))/(-3 + 1))_(0)^(x) = (K)/(2x^(2))` |
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