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The greatest acceleration or deceleration that a train may have is a. The minimum time in which the train may reach fromone station to the other separated by a distance d is5.2d(4) 22 a |
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Answer» option 2 is correct explain it using the second equation o motion u and v for train will be zero. for minimum time maximum acceleration will be needed and hence the distance is d. thus d = 1/2*a*t^2 now time t = root(2d/a) but answer is 4th option |
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