d ANSWER:-Question:WAP to calculate hcf of two numbers.Solution:1. In Java. import java.util.*;public class HCF { public static VOID main(String[] args) { int a, b, r; Scanner sc=new Scanner(System.in); System.out.print("Enter first NUMBER: "); a=sc.nextInt(); System.out.print("Enter second number: "); b=sc.nextInt(); while (a%b!=0) { r=a%b; a=b; b=r; } System.out.println("HCF: "+b); sc.close(); }}2. In Python. a=int(input("Enter first number: "))b=int(input("Enter second number: "))while not a%b==0: r=a%b a=b b=rprint("HCF: ",b)3. In C#include int main() { int a, b, r; PRINTF("Enter first number: "); scanf("%d", &a); printf("Enter second number: "); scanf("%d", &b); while (a%b!=0) { r=a%b; a=b; b=r; } printf("HCF: %d", b); return 0;}4. In C++#include using namespace std;int main() { int a,b,r; cout << "Enter first number: "; cin >> a; cout << "Enter second number: "; cin >> b; while (a%b!=0) { r=a%b; a=b; b=r; } cout << "HCF: " << b; return 0;}Dry Run:Consider two numbers, say 18 and 24a = 18 and b = 24a%b == 0 is false. So, r = a%b = 18a = b = 24b = r = 24Again, a%b == 0 is false. So, r = a%b = 6a = b = 24b = r = 6Now, a%b == 0 is true as 24%6 is true. So, HCF = b = 6Therefore, HCF of 18 and 24 is 6.See the attachment for output ☑.