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The half-life for a reaction at initial concentration of `0.5` and `1.0 "mole litre"^(-1)` are `200 sec` and `100 sec` respectively. The order of the reaction isA. `0`B. `1`C. `2`D. `3` |
Answer» Correct Answer - C `t_(1/(2)) prop (1)/(a^(n-1`))" "(200)/(100) = ((1)/(0.5))^(n-1)` `2 = 2^(n-1) n-1=1" " n = 2` |
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