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The half-life of 2 sample are `0.1` and `0.4` seconds . Their respective concentration are 200 and 50 respectively . What is the order of reaction |
Answer» Correct Answer - b `t_(1//2) prop a^(1-n) implies (0.1)/(0.4) = ((200)^(1-n))/((50)^(1-n)) implies (1)/(4) [(4)/(1)]^(1-n) = [(1)/(4)]^(n-1)` `implies (1)/(4^(1)) = (1)/(4^(n-1)) therefore n - 1 = 1 , n = 2`. |
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