

InterviewSolution
Saved Bookmarks
1. |
The half life of decompoistion of `N_(2)O_(5)` is a first order reaction represented by `N_(2)O_(5)rarrN_(2)O_(4)+1//2O_(2)` After `15`min the volume of `O_(2)` profuced is `9ml` and at the end of the reaction `35ml`. The rate constant is equal toA. `(1)/(15)log_(e).(35)/(26)`B. `(1)/(15)log_(e).(44)/(26)`C. `(1)/(15) log_(e).(35)/(36)`D. None of these |
Answer» Correct Answer - A `k = (2.303)/(t)log.(V_(oo))/(V_(oo)-V_(t))` `= (1)/(t) log_(e).(V_(oo))/(V_(oo)-V_(t))` `= (1)/(15)log_(e).(35mL)/((35-9)mL) = (1)/(15)log_(e).(35)/(26)` |
|