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The half life of radioactive Radon is `3.8 days` . The time at the end of which `(1)/(20) th` of the radon sample will remain undecayed is `(given log e = 0.4343 ) `A. (a) 3.8 daysB. (b) 16.5 daysC. (c) 33 daysD. (d) 76 days |
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Answer» Correct Answer - B Using `N=N_0e^(-lambdat)` where, `lambda=(1n2)/(t_(1//2))=(1n2)/(3.8)` `:.` `N_0/20=N_0e^(-(1n2)/(3.8)t)` Solving this equation with the help of given data we find `t=16.5 days` `:.` Correct option is (b). |
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