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The half-life period for the first order reaction is 693 seconds. The rate constant of this reaction would beA. `0.1 sec^(-1)`B. `0.01 sec^(-1)`C. `0.001 sec^(-1)`D. `0.001 sec^(-1)` |
Answer» Correct Answer - c `t_(1//2) = (0.693)/(k)` Given `t_(1//2) = 693` sec `693 = (0.693)/(k) , k = (693 xx 10^(-3))/(693) , k = 10^(-3) = 0.001 sec^(-1)`. |
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