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The half-life period of a first order process is 1.6 min. It will be 90% completed inA. 0.8 minB. 3.2 minC. 5.3 minD. 1.6 min |
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Answer» Correct Answer - C For first order reaction, `t_(1//2)=(0.693)/(k)` `implies " "k=(0.693)/(1.6)=0.4332" min"^(-1)` Now, for 90% completion, `k=(2.303)/(t)log.(a)/(a-x)` `implies " "0.4332=(2.303)/(t)log.(100)/(10)implies t=5.3min` |
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