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InterviewSolution
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The half-life period of a radioactive element x is same as the mean life time of another radioactive element y. Initially, both of them have the same number of atoms. Then, (a) x and y have the same decay rate initially (b) x and y decay at the same rate always (c) y will decay at a faster rate than x (d) x will decay at a faster rate than yA. `X` and `Y` have the same decay rate initiallyB. `X` and `Y` decay at the same rate alwaysC. `Y` will decay at a faster rate than `X`D. `X` will decay at a faster rate then `Y`. |
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Answer» Correct Answer - C ( c) `(T_(1//2))_x = (t_(mean))_y` `rArr (0.693)/(lamda_x) = (1)/(lamda_y) rArr lamda_x = 0.693 lamda_y` or `lamda_x lt lamda_y` Also rate of decay `= lamda N` Initially number of atoms (N) of both are equal but since `lamda_y gt lamda_x`, therefore, `y` will decay at a faster rate than `x`. |
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