InterviewSolution
Saved Bookmarks
| 1. |
The heat absorbed by the system in going through the cyclic process as shown in figure is A. 30.4 JB. 31.4 JC. 32.4 JD. 33.4 J |
|
Answer» Correct Answer - B In a cyclic process heat absorbed by the system is equal to the work done by the system `therefore` Hence absorbed =work done =area of the given circle `=pir^(2)=pixx((Delta,P)/(2))((DeltaV)/(2))` =`3.14xx((200)/(2))xx10^(3)xx((200)/(2))xx10^(-6)` `=3.14xx100xx10^(3)xx10xx10^(-6)=31.4 J` |
|