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InterviewSolution
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The heat of combustion of ethane gas is `-368 kcal mol^(-1)`. Assuming that `60%` of heat is useful, how many `m^(3)` of ethane measured at `NTP` must be burned to supply heat to convert `50 kg` of water at `10^(@)C` to steam at `100^(@)C`? |
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Answer» Heat required per gram of water `= (90 + 540) cal = 630 cal` Total heat needed for `50 kg` of water `= 50 xx 10^(3) xx 630 kcal` As the efficiency is `60%`, the acid amount of heat required `=(50 xx 10^(3) xx 630)/(60) xx 100 = 52500 kcal` Number of mole of ethane required to produce `52500 kcal` `= (52500)/(368) = 142.663 mol` Volume of `142.663` mole at `NTP = 142.663 xx 22.4` `= 3195.65 L = 3.195 m^(3)` |
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