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The heat of formation of water is `260 kJ`. How much `H_(2)O` is decomposed by `130 kJ` heat ?A. `0.25` molB. 1 molC. `0.5` molD. 2 mol |
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Answer» Correct Answer - C The reaction for the formation of water is as `H_(2) + (1)/(2) O_(2) to H_(2) O , Delta H = 260 kJ … (i)` On reversing Eq. (i) , we get `underset(1 "mol")(H_(2)O) to H_(2) + (1)/(2)O_(2) , ` `Delta H = -260 kJ " " … (ii)` `because` By 260 kJ heat water decomposed = 1 mol `therefore` 130 kJ heat will decompose water = `(1 xx 130)/(260)` = 0.5 mol |
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