1.

The hinge of a door is at a distance of 30 cm from the point of application of force. If a force of 15 N is applied, what is the magnitude of moment of force? *

Answer»

Answer:

the required answer is 4.5 Nm

GIVEN:

  • distance,d = 30cm
  • force ,F = 15 N

TO FIND:

magnitude of moment of force,M

MOMENT OF FORCE:

  • moment of force is also called torque.

  • moment force is defined as the product of force APPLIED and the perpendicular distance

  • moment of force RESULTS in the rotation of object at the point of hinge

FORMULA:

moment of force ,M = f× d

SOLUTION:

STEP 1: TO CHANGE THE UNIT OF DISTANCE.

  • it is necessary to change the unit of distance to standard unit.

  • standard unit of distance is metre

  • 100cm = 1 m

  • so, 30 cm will be 30/100 m

  • so the distance in standard unit is d=0.3

STEP 2: TO FOND THE MOMENT OF FORCE

M=f×d

=15×0.3

M =4.5 Nm

ANSWER:

the magnitude of moment of force is 4.5 Nm


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