The human body contains `18%` carbon by weight, in which `.^(14)C` is `1.56xx10^(-6)` per cent. If the half-life of `.^(14)C` is `5570` year, then the number of disintengration per mintute in the body of this weight is:A. `194`B. `1940`C. `19400`D. `28600`

The human body contains `18%` carbon by weight, in which `.^(14)C` is

1.	The human body contains `18%` carbon by weight, in which `.^(14)C` is `1.56xx10^(-6)` per cent. If the half-life of `.^(14)C` is `5570` year, then the number of disintengration per mintute in the body of this weight is:A. `194`B. `1940`C. `19400`D. `28600`
Answer» Correct Answer - `(d)` Amount of `.^(14)C` in body `= (18 xx w xx 1.56xx10^(-10)xx6.023xx10^(23))/(100xx100xx14)` (where `w` is `wt`. Of body) `:.` rate `= lambda xx` No. of atoms `= (0.693)/(5570xx365xx24xx60)` `xx (18xx1.56xx10^(-10)xx6.023xx10^(23))/(100xx100xx14)w` Rate/Body `wt. = 2.86xx10^(4)` dpm

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The human body contains `18%` carbon by weight, in which `.^(14)C` is `1.56xx10^(-6)` per cent. If the half-life of `.^(14)C` is `5570` year, then the number of disintengration per mintute in the body of this weight is:A. `194`B. `1940`C. `19400`D. `28600`

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