InterviewSolution
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InterviewSolution
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The hydrogen ion concentration of a `10^(-8) M HCl` aqueous soultion at `298 K(K_(w)=10^(-14))` isA. `1.0xx10^(-6) M`B. `1.0525xx10^(-7) M`C. `9.525xx10^(-8) M`D. `1.0xx10^(-8) M` |
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Answer» Correct Answer - B In aqueous solution of `10^(-8) M HCl`, `[H^(+)]` is based upon the concentration of `H^(+) ion` of `10^(-8) M HCl` and concentration of `H^(+) ion` of water. `K_(w)` of `H_(2)O=10^(-14)=[H^(+)][OH^(-)]` or `[H^(+)]=10^(-7) M` (due to its neutral behaviour) So, in aqueous solution of `10^(-8) M HCl`, `[H^(+)]=[H^(+)]` of `HCl+[H^(+)]` of water `=10^(-8)+10^(-7)=11xx10^(-8) M` `1.10xx10^(-7) M` |
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