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The image of an object is at 10 cm from the con cave mirror if focal length of mirror is 15 cm then find the distance of object from mirror |
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Answer» Answer: first at concave mirror u= -15u=−15 ; f= -10f=−10 \dfrac{1}{V}+\dfrac{1}{u}=\dfrac{1}{f} v 1
+ u 1
= f 1
\dfrac{1}{v}-\dfrac{1}{15}= -\dfrac{1}{10} v 1
− 15 1
=− 10 1
v= -30v=−30 then at convex mirror u= -10u=−10 ; f= +15f=+15] \dfrac{1}{v}+\dfrac{1}{u}=\dfrac{1}{f} v 1
+ u 1
= f 1
\dfrac{1}{v}-\dfrac{1}{10}=\dfrac{1}{15} v 1
− 10 1
= 15 1
v= 6v=6 i.e, image is formed at a distance 6cm6cm behind the mirror and it is VIRTUAL |
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