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The initial concentration of `N_(2)O_(5)` in the following first order reaction: `N_(2)O_(5)(g) rarr 2NO_(2)(g)+(1)/(2)O_(2)(g)` was `1.24 xx 10^(-2) mol L^(-1)` at `318 K`. The concentration of `N_(2)O_(5)` after `60 min` was `0.20 xx 10^(-2) mol L^(-1)`. Calculate the rate constant of the reaction at `318 K`.A. `0.0104" min"^(-1)`B. `0.0204" min"^(-1)`C. `0.0304" min"^(-1)`D. `0.0404" min"^(-1)` |
Answer» Correct Answer - C For a first order reaction , `"log"([R]_(1))/([R]_(2))=(k(t_(2)-t_(1)))/(2.303)` `k=(2.303)/((t_(2)-t_(1)))"log"([R]_(1))/[R]_(2)` `=(2.303)/((60min-0min))"log"(1.24xx10^(-2)"mol "L^(-1))/(0.20xx10^(-2)"mol "L^(-1))` `= (2.303)/(60)log6.2" min"^(-1)=0.0304" min"^(-1)` |
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