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The inner diameter of a cylindrical wooden pipe is 24 cm and its outer diameter is 28 cm. The length of the pipe is 35 cm. Find the mass of the pipe, if 1 cm3 of wood has a mass of 0.6 g. |
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Answer» Volume=Volume of outer cylinder-Volume of inner cylinder =`piR^2h-pir^2h` =`pih(R^2-r^2)` =`22/7*35(14^2-12^2)` =`5720cc` Mass=0.69*5720 =3432g. |
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