The input resistance of a common emitter transistor amplifer, if the output resistance is `500 K Omega`, the current gain `alpha = 0.98` and power gain is `6.0625 xx 10^(6)`, isA. `198 Omega`B. `300Omega`C. `100Omega`D. `400Omega`

The input resistance of a common emitter transistor amplifer, if the o

1.	The input resistance of a common emitter transistor amplifer, if the output resistance is `500 K Omega`, the current gain `alpha = 0.98` and power gain is `6.0625 xx 10^(6)`, isA. `198 Omega`B. `300Omega`C. `100Omega`D. `400Omega`
Answer» Correct Answer - A `alpha=0.98` `beta=(alpha)/(1-alpha)=(0.98)/(1-0.98)=49` `A_(p)=beta^(2)(R_(L))/(R_("in"))` `6.0625xx10^(6)=(49)^(2)xx(500xx10^(3))/(R_(in))` `R_("in")=198Omega`

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The input resistance of a common emitter transistor amplifer, if the output resistance is `500 K Omega`, the current gain `alpha = 0.98` and power gain is `6.0625 xx 10^(6)`, isA. `198 Omega`B. `300Omega`C. `100Omega`D. `400Omega`

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