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The input resistance of a silicon transistor is `665Omega`. Its base current is changed by `15muA` which results in the change in collector current by `2mA`. This transistor is used as a common emitter amplifier with a load resistance of `5kOmega`. What is the voltage gain of the amplifier.A. 1002B. 1004C. 1006D. 1008 |
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Answer» Correct Answer - A `R_(i)=665 Omega, delta I_(b)=15 muA , deltaI_(c)=2mA` `R_(0)=5 K Omega, A_(v)= ?` `A_(v)=beta(R_(0))/(R_(i))=(deltaI_(c))/(deltaI_(b))*(R_(0))/(R_(i))` `=(2xx10^(-3)xx5xx10^(3))/(15xx10^(-6)xx665)` `=(10xx10^(6))/(15xx665)` `=(10000xx10^(3))/(9975)` `=1.002xx10^(3)` =1002 |
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