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The intensity of a plane progressive wave of frequency `1000 Hz` is `10^(-10) Wm^(-2)`. Given that the speed of sound is `330 m//s` and density of air is `1.293 kg//m^(3)`. Then the maximum change in pressure in `N//m^(2)` isA. `3 xx 10^(-4)`B. `3 xx 10^(-5)`C. `3 xx 10^(-3)`D. `3 xx 10^(-2)` |
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Answer» Correct Answer - A `I = (p_(0)^(2))/(2 rho v)` `p_(0) = sqrt(2 pv I) = sqrt(2 xx 1.293 xx 330 xx 10^(-10))` `= 30 xx 10^(-3) = 3 xx 10^(-4) N//m^(2)` |
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