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The intercepts on x-axis made by tangents to thecurve, `y=int_0^x|t|dt , x in R ,`which are parallel to the line `y""=""2x`, are equalto(1) `+-2`(2) `+-3`(3) `+-4`(4) `+-1` |
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Answer» `y = int_0^x |t| dt` `dy/dx = |x|= 2` `x +- 2` when `x=2` `y = int_0^2 |t|dt` `= |t|^2/2 = 2` when `x=-2` `y= - int_0^-2 |t| dt` `= - [|t|^2/2]` `y= -2` now,`y-2 = 2(x-2)` `y-2 = 2x - 4` `y= 2x -2` `y-2 = -2(x+2)` `y-2 = -2x - 4` `y = -2x-2` so, by solving `2x-2= 0` `x=1` `0= -2x-2` `x=-1` `x= +- 1` Answer is option 4 |
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