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The ionization constant of ammonium hydroxide is `1.77xx10^(-5)` at `298 K`. Hydrolysis constant of ammonium chloride isA. `5.65xx10^(-12)`B. `5.65xx10^(-10)`C. `6.50xx10^(-12)`D. `5.65xx10^(-13)` |
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Answer» Correct Answer - B `NH_(4)Cl` is a salt of strong acid and weak base, so `K_(h)=(K_(w))/(K_(b))=(10^(-14))/(1.77xx10^(-5))=5.65xx10^(-10)` |
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