The latent heat of vapourisation of a liquid at `500K` and `atm` pressure is `30kcal mol^(-1)`. What will be change in internal energy of `3mol` of liquid at same temperature?A. `13.0 kcal`B. `-13.0 kcal`C. `27.0 kcal`D. `-27.0 kcal`

The latent heat of vapourisation of a liquid at `500K` and `atm` press

1.	The latent heat of vapourisation of a liquid at `500K` and `atm` pressure is `30kcal mol^(-1)`. What will be change in internal energy of `3mol` of liquid at same temperature?A. `13.0 kcal`B. `-13.0 kcal`C. `27.0 kcal`D. `-27.0 kcal`
Answer» `:. DeltaH = DeltaU + DeltanRT` `:. DeltaH = 300 kcal` `3H_(2)O(l) rarr 3H_(2)O(v)` `Deltan = 3 - 0 = 3` `rArr 30 = DeltaU +3 xx 0.0821 xx 500 xx 10^(-3)` `DeltaU = 27 kcal`

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The latent heat of vapourisation of a liquid at `500K` and `atm` pressure is `30kcal mol^(-1)`. What will be change in internal energy of `3mol` of liquid at same temperature?A. `13.0 kcal`B. `-13.0 kcal`C. `27.0 kcal`D. `-27.0 kcal`

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