InterviewSolution
Saved Bookmarks
| 1. |
The lattice energy of solid `NACl` is `180K. Cal mol^(-1)`. The dissolution of the solid in water in the form of ions is endothermic to the extent of `1 K.cal mol^(-1)`. If the hydration energies of `NA^(+)` and `Cl^(-)` are in ratio `6 : 5`, what is the enthalpy of hydration of `NA^(+)` ionA. `-85.6 K. cal mol^(-1)`B. `-97.5 K.cal mol^(-1)`C. `-182.6 K.cal mol^(-1)`D. `+100K. Cal mol^(-1)` |
|
Answer» Correct Answer - B `DeltaH_(sol^(n))=DeltaH_(L.E)+DeltaH_(H.E)` |
|