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The length (16 cm) and area of cross section(4 cm²) of a copper wire are increased by 25% each.If the resistance of original wire is 8 S2, find the newresistance. |
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Answer» SOLUTION : (i)`Rpropl//A` (ii) ` (R_(1))/(R_(2))=(l_(1))/(l_(2))XX(A_(2))/(A_(1))` (iii)`l_(2)=l_(1)+0.25l_(2)` `A_(2)=A_(1)+0.25A_(1)` (iv)`8 Omega` |
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