1.

.The length of a seconds pendulum is increasedby 1%. How many seconds it will lose per day?(a) 432s(d) 3737 s (e) 3927 s(b) 864 s(c) 3427 s

Answer»

Pendulum period in secondsT ≈ 2π√(L/g)L is length of pendulum in metersg is gravitational acceleration = 9.8 m/s²

there are 86400 seconds in a day.

dT/dL = (1/2)2π√(1/g)√1/L) = π√(1/Lg)dT = π/√(gL) dL

dL/L = 0.01 (ie, 1%)dL = 0.01LdT = π/√(gL) (0.01)LdT = (0.01)(π/√g) L/√LdT = (0.01)(π/√g)√LdT = (0.01)(π√(L/g))dT = (0.01)(1/2)(2π√(L/g))dT = (0.005)TdT = (0.005)(86400) = 432 seconds



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