1.

The length of a side of a cube is 10cm; if an error of 0.05cm is made in measuring the side, then what is the value of percentage error in calculating its volume?(a) 1.65(b) 1.45(c) 0.015(d) 1.5This question was posed to me by my school principal while I was bunking the class.My enquiry is from Application of Derivative for Error Determination topic in chapter Application of Derivatives of Mathematics – Class 12

Answer»

The correct answer is (d) 1.5

Easiest explanation: Let, v cubic cm be the volume of the cube of the cube of side x cm.

Then, v = x^3

Thus, dv/dx = d/dx(x^3) = 3x^2

Now, dv = dv/dx * δx = 3x^2 * δx

By PROBLEM, x = 10 and δx = 0.05

Therefore, approximate ERROR = dv = 3 * 10^2 * 0.05 = 15 cc cm.

Hence, RELATIVE error = dv/v = 15/10^3 = 0.015

Thus, percentage error = relative error * 100 = 0.015 * 100 = 1.5



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