InterviewSolution
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InterviewSolution
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The length of a steel wire is `l_(1)` when the stretching force is `T_(1)` and `l_(2)` when the stretching force is `T_(2)`. The natural length of the wire is |
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Answer» Let l and A be the original length and area of cross-section of the metal wire. Change in length in the first case = `(l_(1)-l)` Change in length in the second case` = (l_(2)-l)` `:. Y=(T_1)/(A) xx (l)/(l_(1)-l) = (T_2)/(A) xx (l)/(l_(2)-l)` or `T_(1)l_(2)-T_(1) l=T_(2) l_(1)-T_(2)l` or `l(T_(2)-T_(1)) = T_(2) l_(1)-T_(1)l_(2)` or `l=(T_(2)l_(1)-T_(1)l_(2))/(T_(2)-T_(1))`. |
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